Chinese smartphone manufacturer ZTE has scheduled an event on April 6 in China where it is expected to unveil the Nubia Z17 mini. The phone was spotted on TENAA a few days ago which confirmed its specifications. Now, a new device with model number NX575J has been certified by TENAA. It sports a 5.5-inch display, 4GB RAM and 4390mAh battery. In addition to this, the device was also spotted on Geekbench, confirming the 4GB RAM and a MT6750 SoC.
According to the TENAA listing the device measures 154 × 76.4 × 8.2mm in size and weighs around 185g. As mentioned above, it sports a 5.5-inch OLED display with a resolution of 720×1280p. Under the hood, the phone is likely to run on an MT6750 SoC with 4GB of RAM and have 64GB of internal storage. The device is likely to boot Android 6.0 Marshmallow with Nubia 4 user interface on top.
In terms of the camera specifications, the Nubia NX575J will feature a 13-megapixel rear-facing camera and a 16-megapixel front-facing camera. Connectivity-wise, the phone will have 4G VoLTE support, Wi-Fi 802.11 ac, Bluetooth and a 3.5mm audio jack.
The Nubia NX575J is said to be available in Platinum Black and Gold colours. As for its launch, the company might unveil the device along with Nubia Z17 mini on April 6 in China.
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