The Vivo V1928A, that was previously listed on TENAA, has appeared on Geekbench today. On paper as well as with images, the handset resembles the Vivo U10 that is slated for a release on September 24th in India as an online-exclusive device. Vivo has already teased a few features of the new U series where U stands for ‘Unstoppable’. In addition to the Vivo U series, Vivo is also readying itself for the V17 Pro on September 20th.
Coming to the Geekbench listing, the V1928A is uncovered with the Snapdragon 665 SoC which is often sighted as ‘trinket’. Previous devices like the Mi CC9e also appeared on Geekbench with the same name and hence it is safe to conclude the V1928A or the alleged Vivo U10 has the Snapdragon 665 SoC. It also has 4GB of RAM as well as Android 9.0 Pie. It has a base frequency of 1.80Ghz though and has clocked an understandable score of 5,752 in the multi-core test.
As for the TENAA listing, the Vivo V1928A packs a 6.35-inch display with a 720 x 1544p resolution. Notably, TENAA database logged a 2.0GHz octa-core processor with 3GB/4GB of RAM and 32GB/64GB of onboard storage expandable up to 256GB. Images show triple camera sensors on the rear with a 13MP + 8MP + 2MP composition. The battery on the Vivo V1928A is 4,800mAh and the Vivo U10’s teased 5,000mAh juice pack. It will also be assisted by an 18W fast charging system. Vivo’s official promo material claims 4.5 hours of usage with just 10 minutes of charge with the U10.
Now, there’s no way to confirm that the V1928A is indeed the Vivo U10 but TENAA images match the promo material exactly as well as a few specifications. There could be a few variations in the China model compared to India but we don’t know if Vivo will rebrand the handset as something else on its home turf.